求下列不定积分：∫√[sin(x/2)+cos(x/2)]2dx．
求下列不定积分：∫√[sin(x/2)+cos(x/2)]2dx．
【正确答案】：∫[sin(x/2)+cos(x/2)2]dx=∫(1+sinc)dx=x-cosx+c．
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