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设矩阵A=
(120
3-1-2),
B=
(-10-2
021),
则A-3B=____
分类:
线性代数(经管类)(04184)
发表:2024年09月12日 10时09分12秒
作者:
admin
阅读:
(12)
设矩阵A=
(120
3-1-2),
B=
(-10-2
021),
则A-3B=____
【正确答案】:(4 2 6 3 -7 -5)
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