更换积分次序后∫0-1dy∫y√yf(x,y)dx=()
更换积分次序后∫0-1dy∫y√yf(x,y)dx=()
A、∫01dx∫xx2f(x,y)dy
B、∫0-1dx∫x√xf(x,y)dy
C、∫x√xdx∫01f(x,y)dy
D、∫01dx∫x2xf(x,y)dy
【正确答案】:D
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