若函数f(x,y)=ln(x-√x2+y2)(x﹥>y﹥0),,则f(x+y,x-y)=____.
若函数f(x,y)=ln(x-√x2+y2)(x﹥>y﹥0),,则f(x+y,x-y)=____.
【正确答案】:f(x+y,x-y)=ln[(x+y)-√((x+y)2-(x-y)2)]=2ln(√x-√y)
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