求下列各式的极限.
(1)limx→0,y→0xy/(√1+xy)-1;
(2)limx→0,y→0sinxy/x
求下列各式的极限.
(1)limx→0,y→0xy/(√1+xy)-1;
(2)limx→0,y→0sinxy/x
【正确答案】:(1)limx→0,y→0xy/(√1+xy)= limx→0,y→0xy((√1+xy)+1)/(1+xy-1)= limx→0,y→0[(√1+xy)+1] (2)limx→0,y→0sinxy/x=limx→0,y→0(sinxy/xy)y=1•0=0.
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