计算不定积分∫[(4sin<sup>3</sup>x-1)/sin<sup>2</sup>x)]dx

计算不定积分∫[(4sin³x-1)/sin²x)]dx

计算不定积分∫[(4sin³x-1)/sin²x)]dx
【正确答案】：∫[(4sin³x-1)/sin²x]dx=∫[(4sinx-1(/sin²x)]dx=4∫sinxdx-∫csc²xdx=-4cosx+cotx+C

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