limx→1[sin(x-1)/(x2+x-2)]=()
limx→1[sin(x-1)/(x2+x-2)]=()
B、1/3
C、1
D、1/2
【正确答案】:B
【题目解析】:limx→1sin(x-1)/(x2+x-2)=limx→1sin(x-1)/[(x-1)(x+2)]=limx→1sin(x-1)/(x-1)•limx→1[1/(x+2)]=1+(1/3)=1/3.
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