设y=(1+x)ln(1+x+√2x+x2)-√2x+2,求dy
设y=(1+x)ln(1+x+√2x+x2)-√2x+2,求dy
【正确答案】:y′=In(1+x+√2x+x2)+(1+x)•[1+(2+2x)/2√x+x2]/(1+x+√2x+x2)-(2+2x)/2√2x+x2 =In(1+x+√2x+x2) 所以dy=In(1+x√2x+x2)dx.
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