求∫[x4/(x2+1)]dx.
求∫[x4/(x2+1)]dx.
【正确答案】:(1/3)x3-x+arctanx+C 分析 ∫[x4/(x2+1)]dx=∫[(x4-1+1)/(x2+1)]dx =∫[x2-1+1/(x2+1)]+dx =(1/3)x3-x+arctanx+C
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