∫x√(1-x2)arcsinxdx
∫x√(1-x2)arcsinxdx
【正确答案】:∫x√(1-x2)arcsinxdx =-1/2∫(1-x2)1/2•arcsinxd(1-x2) =-1/3arcsinxd(1-x2)3/2 =-1/3√(1-x2)3•arcsinx+1/3∫(1-x2)3/2darcsinx =-1/3√(1-x2)3•arcsinx+1/3∫(1-x2)dx =-1/3√(1-x2)3•arcsinx+1/3x-1/9x3+C
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