设z=ln(x+ey),则∂2z/∂x∂y=()
设z=ln(x+ey),则∂2z/∂x∂y=()
A、ex/(ex+ey)2
B、-ex+y/(ex+ey)2
C、ex+y/(ex+ey)2
D、ey/(ex+ey)2
【正确答案】:B
【题目解析】:∂z/∂x=ex/(ex+ey),∴∂2z/∂x∂y=(∂/∂y)(∂z/∂x)=(∂/∂y)[ex/(ex++ey)]=-ex•ey/(ex+ey)2=-ex+y/(ex+ey)2
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