设y=x2(lnx-1)-(1-x2)lnx,求(dy/dx)∣x=e
设y=x2(lnx-1)-(1-x2)lnx,求(dy/dx)∣x=e
【正确答案】:∵[x2(lnx-1)]'=2xlnx-x,[(1-x2)lnx]'=-2xlnx+(1-x2)/x=-2xlnx-x+1/x,∴y'=2xlnx-x-(-2xlnx-x+1/x)=4xlnx-1/x,y'∣x=e=4e-1/e
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