计算反常积分:
+∞0x/(1+x2)2dx
计算反常积分:
+∞0x/(1+x2)2dx
【正确答案】:∫+∞0x/(1+x2)2dx =1/2∫+∞01/(1+x2)2d(1+x2) =-1/2×1/(1+x2)|+∞0 =-1/2×(0-1) =1/2
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