企源知识库

计算下列反常积分：
∫^+∞₀1/(x²+2x+2)dx
【正确答案】：∫^+∞₀1/(x²+2x+2)dx =∫^+∞₀1/[1+(x+1)²]d(x+1) =arctan(x+1)|^+∞₀． =π/2-π/4 =π/4