设二维连续随机向量(X,Y)的概率密度
f(x,y)={1/8(x+y)0≤x≤2,0≤y≤2;
{0其他.
求E(X),E(Y),Cov(X,Y),ρXY
设二维连续随机向量(X,Y)的概率密度
f(x,y)={1/8(x+y)0≤x≤2,0≤y≤2;
{0其他.
求E(X),E(Y),Cov(X,Y),ρXY
【正确答案】:E(X)=∫+∞-∞+∞-∞xf(x,y)dxdy , =∫20x[∫201/2(x+y)dy]dx=6/7, E(Y)=∫2020[y•1/2(x+y)dy]dx=6/7. Cov(X,Y)=E[(x-7/6)(Y-7/6)] =∫2020(x-7/6)(y-7/6)1/8(x+y)dxdy =∫2020[xy-(7/6)x-(7/6)y+(7/6)2]1/8(x+y)dy}dx =-(1/36) D(X)=E[X-E(X)]2 =∫+∞-∞+∞-∞[x-E(X)]2f(x,y)dxdy =∫2020(x-7/6)21/8(x+y)dxdy=11/36. D(Y)=11/36. 所以ρXY=Cov(X,Y)/√D(x)=D(Y)=[-(1/36)/11/36]=-(1/ 11).
Top